View Single Post
  #4  
Old October 17th, 2009, 02:48 AM
CaptainBlack's Avatar
CaptainBlack CaptainBlack is offline
Grand Panjandrum
 
Join Date: Nov 2005
Location: South of England
Posts: 12,190
Country:
Thanks: 770
Thanked 3,953 Times in 3,191 Posts
CaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond reputeCaptainBlack has a reputation beyond repute
Default

Quote:
Originally Posted by ercan View Post
Thanks for your interest, CaptainBlack. But I couldn't understand. Do you mean that I have to divide the period to T (2*pi/0.01). What is its function?
What I mean is that to compute the z-transform it would help if the period of the waveform were a multiple of the sampling interval. For example if the frequency were 1 Hz (period 1 second) then a sampling frequency of 100 Hz (sampling interval of 10ms) would give exactly 100 samples in a single cycle of the waveform. Then we take the first 100 terms of the z-transform series and sum them, and every following set of 100 terms is a z^{-100} times the sum of the previous set, and se we have a geometric series which we can sum (for z<1) to give the final answer. (this is the equivalent to the sum of time shifted basic waveforms)

An alternative approach is to take the Laplace transform for the signal, and then use the relationship between the ZT and LT to move from the s-domain to the z-domain.

CB
__________________
Truth does not change because it is, or is not, believed by a majority of the people.

Giordano Bruno

Last edited by CaptainBlack; October 17th, 2009 at 03:32 AM.
Reply With Quote