Thread: mx=sin x
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Old November 2nd, 2009, 07:16 AM
Aquafina Aquafina is offline
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Quote:
Originally Posted by Grandad View Post
Hello AquafinaAre you sure about that? See the attached diagram.
Hi Grandad! How does that help? Both the gradients are less than 1, so it doesn't disprove what I said?

Quote:
Originally Posted by Grandad View Post
You obviously can't mean ab = ba. Do you mean a^b = b^a?
Yes sorry typo, I have corrected it now to a^b = b^a. Any ideas with this?
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