View Single Post
  #1  
Old November 2nd, 2009, 09:33 AM
Jluse7 Jluse7 is offline
Newbie
 
Join Date: Sep 2009
Posts: 24
Country:
Thanks: 0
Thanked 1 Time in 1 Post
Jluse7 is on a distinguished road
Default Please help! I dont understand oblique asymptotes very well

Here's the problem- Sketch the graph of y=f(x)= x^3+x^2-12x.
Complete the table. x^2-2x-8
Include all intercepts and asymptotes on the graph.

Interval
Test point k
f(k)
sign of f
position of graph

Here's what I put.
x-int= (-4,0(3,0)
y-int= (0,0)
horizontal asymptote= I'm not sure if this is right, but i got x+3
vertical asymptote= x=4 x=-2
Reply With Quote