Thread: Laplace transform
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Old November 5th, 2009, 03:14 AM
harbottle harbottle is offline
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Default Laplace transform
Find the Laplace transform of t \sin(2t + 5) = G(s)

So if F(s) = \mathcal{L}\{\,\sin(2t+5);t \to s\}

Then G(s) = -F'(s)

But F(s) = \;?

Any help would be appreciated, thankyou!
Last edited by harbottle; November 5th, 2009 at 02:45 PM.
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