Thread: prove H is an abelian group
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Old November 5th, 2009, 07:41 PM
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Quote:
Originally Posted by apple2009 View Post
g²=I for all h is an element of H.
a)Prove: H is an abelian group
b)Prove: Suppose |H|<∞. Let {h₁,h₂,…..hn} be minimal set of generators for H. The |H|=2^n
I think it should be "then \left|H\right|=2^n. If so, I think you ought to be able to make a contrived answer from the way the question is posed. What is significant looking about that expression?
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