Thread: system [of equations]
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Old November 6th, 2009, 03:31 AM
HallsofIvy HallsofIvy is offline
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Dividing the first equation by the second eliminates Y and gives
\frac{1+\frac{X+2}{100}}{1+\frac{X}{100}}= \frac{2350}{3100}

Multiplying both numerator and denominator on the left by 100 gives
\frac{102+ X}{100+ X}= \frac{2350}{3100}.
That should be easy to solve for X.
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