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Old November 7th, 2009, 03:09 AM
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A isosceles trapezium named ABCD has just been created from nothing. The sides (AB) and (CD) are parallel. Therefore, we have :

(AB + CD)(BC + AD) = AC \times BD

Note that BC = AD (since the trapezium is isosceles)
Therefore :

(AB + CD)(2BC) = AC \times BD

Now draw such a trapezium and think of as many useful things as you can : Thales, Pythagoras, Trigonometry, Vectors, anything. Then try putting it all together to substitute formulas into the original equation, so as to prove that the sum of the parallel sides times the sum of the non-parallel sides equals the product of the diagonals. Does it help ?
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