Thread: derivative of cot x
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Old November 7th, 2009, 03:20 PM
saweetness saweetness is offline
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Default derivative of cot x
use the quotient rule to show that
d/dx cotx = -csc^2 x
(hint: Write cotx = cosx/sinx)

...

cotx = cosx/sinx

:S

please help THANKS!
Last edited by mr fantastic; November 7th, 2009 at 08:40 PM. Reason: Changed post title
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