Thread: Problem 22
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Old April 20th, 2007, 03:43 AM
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Quote:
Originally Posted by Chronos View Post

I assumed his question was more complicated than that.

That's because you assumed the functions involved are continuous! It's pretty trivial in that case

If however they are assumed only integrable (as they should - ps. I love Hacker's problems, coz they are almost never "well posed", and that's exactly what makes a problem interesting ) than we can just apply Cauchy-Schwartz:



Q(uite)E(asily)D(oneth).


For 2, this came to my mind. Consider a tangent to the circle. Rotating this by the touching point, for an angle s ε (0,π) we obtain a chord of the circle, of length say l(s)>0. This function is defined on (0,π), is continuous, and can be extended to a function continuous on [0,π] by the (obvious) l(0)=l(π)=0. So it must attain a maximum in (0,π). We now see it is increasing for s<π/2 and decreasing for s>π/2, so the maximum is attained for s=π/2 - this chord is exactly the diameter.
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