Quote:
Originally Posted by ThePerfectHacker  Not every continously differenciable function is analytic.*
*)By analytic I mean it has a power series expansion on  . |
Yes I know, but it illurstates the point nicely.
(though the Stone-Weiestrauss theorem applies, I don't think this is adequate
to do the analysis with polynomial approximations instead, though it would be
nice if it did).
RonL