Quote:
Originally Posted by ThePerfectHacker 2)Let  be distinct integers from  not necessarily in that order. Show that if  is odd then  is an even number. |
As

are distinct integers from

they are infact a permutation of

, so one of the

's is

.
Hence one of the terms

is zero so the product is zero, and so even irrespective of the parity of

.
Or have I misread the question.
RonL