Thread: Problem 29
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Old July 2nd, 2007, 10:18 AM
mathisfun1 mathisfun1 is offline
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Suppose that no two people shake hands the same number of times. Let k be the number of people who shake hands at least once. Order the people from 1 to k by their number of handshakes in ascending order. Each person must shake hands at least one more time than the person before him. Thus the kth person must have shaken hands at least k times. But there are only k people. Contradiction.