Thread: differential equations
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Old July 12th, 2007, 10:35 AM
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Originally Posted by emily28 View Post
after doing some reading on intergrating factors, from



ive used the intergrating factor, whereby f(x) = -4x and a(x) = 4

so g(x)= exp^(intergral of 4 dx)

so g(x) = e^{4x}

now using the formula y= 1/g(x).[intergral of f(x)g(x) dx]

so y=1/e^{4x} [intergral -4xe^{4x}]

is this correct and how would i carry on from this?
yes, that is fine, and incidentally, that is exactly the process i described to you above. i tried to save you the trouble of trying to get it from you text book, sometimes those things are ... let's just say, I hate the text that i used for differential equations. the only thing i like about it is that it gives the answers for even as well as odd problems, which is rare for textbooks to do
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