
September 5th, 2007, 11:40 AM
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Hello, ThePerfectHacker!
Drag your cursor between the asterisks. *
Consider a board n inches long.
It is marked with n-1 inch-marks.
We will cut it (on the inch-marks) into k pieces.
So we will make k-1 cuts.
There are: C(n-1, k-1) ways to choose the cuts.
* Quote: Now try to see how many partitions (again not counting order)
exist for a given integer . | *
We have a board n units long with n-1 inch-marks.
For each of the n-1 inch-marks, there are two choices: cut or don't cut.
Therefore, there are: 2^{n-1} possible partitions.
(This includes an intact, uncut board.)
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