Thread: Trig Substitution
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Old October 1st, 2007, 08:43 PM
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\int\sin^4x\cdot\cos^2x\,dx=\int\sin^4x\,dx-\int\sin^6x\,dx

From here you can use the identity \cos2x=\cos^2x-\sin^2x

It's messy, I hate this integral.
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