Thread: Simplifying and/or Computing problems
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Old October 2nd, 2007, 09:46 AM
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Quote:
Originally Posted by killasnake View Post
2^Logx = 2^log4 x
= 4^3x
I presume "Log" is log_{10}?

Use the change of base formula:
log_{10}(x) = \frac{log_2(x)}{log_2(10)}

So
2^{log_{10}(x)} = 2^{\frac{log_2(x)}{log_2(10)}}

= \left ( 2^{log_2(x)} \right )^{1/log_2(10)}

= x^{1/log_2(10)} \approx x^{0.30103}

-Dan
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