Thread: Not L'Hopital rule
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Old October 5th, 2007, 09:50 AM
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Quote:
Originally Posted by Joyce View Post
limx->infinite ((9X+1)^1/2)/((X+1)^1/2)


...
Hi,

\lim_{x \to \infty}{\frac{\sqrt{9x+1}}{\sqrt{x+1}}} = \lim_{x \to \infty}{\frac{3 \sqrt{x} \cdot \overbrace{\sqrt{1+\frac1{9x}}}^{\text{limit is 1}}}{\sqrt{x} \cdot \underbrace{\sqrt{1+\frac1x}}_{\text{limit is 1}}}} = 3
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