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psychocostin · #3 October 10th, 2007, 02:59 PM

$\omega$ can be calculated with the equation ${\omega} = \frac{2\pi}T$

where $T$ is the period in time for one cycle or oscillation. In the case of the harbour, if working in hours, $T = 12$ , or if working in seconds $T = 12 * 60 * 60$ .

In the question why did they put "If d is the depth of the water above the mean depth"? Why mention of water ABOVE the mean depth?

So then i guess if they're looking for the answer in hours it would be:

$d = 5 \ \cos \frac{1}{2}t$