Thread: Proving Trig Equations
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Old October 11th, 2007, 04:22 PM
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Rewrite #1 and make the cancellations.

\frac{sin^{2}x-tanx}{cos^{2}x-cotx}

sin^{2}x-tanx=tanx(sinxcosx-1)

cos^{2}x-cotx=\frac{sinxcosx-1}{tanx}
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