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mi986 · #1 October 27th, 2007, 05:59 AM

Hey, could someone please check if I simplified this problem correctly?

$\frac {(2^{(a+b)}x^{2b})^{(a-b)}}{(\frac {2^ax}{x^{-b}})^a*(\frac {x^{(a-b)}}{2^b})^b}$

First I got rid of the exponents by multiplying.

= $\frac {2^{(a^2-b^2)}x^{(2ab-2b^2)}}{(\frac {x^{(ab-b^2)}}{2^{b^2}})*(\frac {2^{a^2}x^a}{x^{-ab}})}$

Then I simplified and combined the bottom fractions.

= $\frac {2^{(a^2-b^2)}x^{(2ab-2b^2)}}{x^{(2ab-b^2+a)}2^{(a^2-b^2)}}$

And then repeated that step and got this answer.

$= \frac {1}{x^{b^2+a}}$

Thanks in advance.

Mi986