Thread: Exponents, check.
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Old October 27th, 2007, 10:00 AM
Soroban Soroban is offline
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Hello, mi986!

I can't follow your second line . . .

Quote:
\displaystyle{\frac{\left(2^{a+b}\cdot x^{2b}\right)^{a-b}}{\left(\frac {2^ax}{x^{-b}}\right)^a*(\frac {x^{a-b}}{2^b})^b}}

We have: .\frac{2^{a^2-b^2}\cdot x^{2ab -b^2}}{\frac{2^{a^2}\cdot x^a}{x^{-ab}} \cdot \frac{x^{ab-b^2}}{2^{b^2}}} \;= \;\frac{2^{a^2-b^2}\cdot x^{2ab-b^2}}{2^{a^2-b^2}\cdot x^{a + 2ab -b^2}} \;=\;\frac{1}{x^a}
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