Thread: Problem 40
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Old November 13th, 2007, 06:57 PM
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Quote:
Originally Posted by ThePerfectHacker View Post
How can f(x) = n+1? It is a function, how is that a function?
if n \in Z^+, then it can be thought as a constant function, right?
even if x^n is a sequence of fucntion, then that f(x) can be thought as a sequence of constant function..

then if convergence is at stake, then can we take f(x) = x^2n + 3x^2 = (n+3)x^2.. this is just a hunch..
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