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Old November 14th, 2007, 11:29 AM
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Quote:
Originally Posted by niyati View Post
The divergence you calculated easily was because of the nth term test, right?
No. well, i don't know if that's what you call it, but i used the Test for Divergence.

recall the theorem:

Theorem: If \sum a_n converges, then \lim a_n = 0

the contrapositive of this theorem is:

The Test For Divergence: If \lim a_n \ne 0, then \sum a_n diverges
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