Okay, I think I have found a way to calculate it, but I would need computer software to make it work
so we need to know the probability that

is true. Lets modify the equation to make it more workable.
Add 4A
Square root (B must be positive because it is taken from a set of positive integers)
So now we need to find the probability that this is true for A and B are elements of {1,2,3,...,2007}
So if we assume, A we can figure out the probability for this to be true for B, based on some specific A. In this case,

will give us the number of possibilities that B can be which will satisfy the equations. Then divide that by 2007 (the total number of possibilities that B can be, including those that do and those that do not satisfy the equations), and that will give you the percentage that the equations can be satisfied. Meaning cd=A and c+d=B is true (if A is true).
So for any A, the probability that it has real factors whose sum is B is
And so because any given A has a 1 in 2007 chance of being true, then we can multiply that probability against the probability that B will be true for that A, and then count the total probabilities for each A.
Now we just need to count them all. I'm not very familiar with summation notation, but I think this is correct
As i cycles through every value, it will calculate the odds for an A of that value having a B that will satisfy cd=A and c+d=B, then add it to the running total, and when it is done there should be a percentage, between .96 and 1
Okay, so I don't actually know how to do that, (well, I know what it means, but I don't care to sit here for 2007 iterations and calculate the odds) but I think that it is the answer.
Does anyone know an online site which can do this type of equation? If not, perhaps someone can create a quick program to do it (I used to know how to, but it's been too long

)
Edit: Looks like if you have a graphing calculator, you can do it
Summation (Sigma) Notation Using the Graphing Calculator I, unfortunately, do not have a graphing calculator, but if any of you would plug it in for me, I'd +rep you ^_^ (that's worth like an entire point)