Thread: Problem 40
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Old November 16th, 2007, 12:25 AM
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Originally Posted by angel.white View Post
Okay, I found a site that will calculate these:
Sigma
\sum^{2007}_{i=1}\frac{2007-floor(2\sqrt{i})}{4028049}=.970475036426
So about 97.05%
^_^

Is that the correct answer?

That is the correct value for the sum you give.

RonL
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