Thread: Confused by integration!
View Single Post
  #2  
Old December 7th, 2007, 05:10 AM
Krizalid's Avatar
Krizalid Krizalid is online now
Math Engineering Student

  
Join Date: Mar 2007
Location: Santiago
Posts: 3,027
Country:
Thanks: 82
Thanked 1,350 Times in 1,077 Posts
Krizalid has a brilliant futureKrizalid has a brilliant futureKrizalid has a brilliant futureKrizalid has a brilliant futureKrizalid has a brilliant futureKrizalid has a brilliant futureKrizalid has a brilliant futureKrizalid has a brilliant futureKrizalid has a brilliant futureKrizalid has a brilliant futureKrizalid has a brilliant future
Send a message via MSN to Krizalid
Default
Since you have a sum, integrate each term separately:

\int {\sec x\,dx} = \int {\sec x \cdot \frac{{\sec x + \tan x}}{{\sec x + \tan x}}\,dx} .

And for the another piece \int {\tan x\,dx} = \int {\frac{{\sin x}}{{\cos x}}\,dx} = - \int {\frac{{(\cos x)'}}{{\cos x}}\,dx} .
Reply With Quote