Thread: logarithms?!
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Old January 2nd, 2008, 09:09 AM
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Originally Posted by lemon301 View Post
I never caught on to logarithms, so anything would help. I need help solving these two problems, but if anyone can direct me somewhere that really explains logarithms it would be a great help!

Find the value of log 50 - log 5, where log is the base 10 logarithm.

Evaluate log(v3)27.
I didnt really know how to type that out. It should be log (down 3) 27. Would the down 3 be the base? I just don't understand what to do with it.
Hello,

\log(a) - \log(b) = \log\left(\frac ab\right)

Use this property to do your problem. You should come out with 1.

\log_{3}(27) = \log_{3}(3^3) Now you can easily determine the value of the logarithm.
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