Thread: logarithms?!
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Old 01-02-2008, 11:45 AM
lemon301 lemon301 is offline
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Quote:
Originally Posted by earboth View Post
Hello,

\log(a) - \log(b) = \log\left(\frac ab\right)

Use this property to do your problem. You should come out with 1.

\log_{3}(27) = \log_{3}(3^3) Now you can easily determine the value of the logarithm.
So \log_{3}(3^3) would just simplify out to log 3, correct?
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