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Old January 3rd, 2008, 05:20 AM
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Quote:
Originally Posted by geton View Post
I’ve another problem,


Prove that the sum of the first 2n multiples of 4 is 4n(2n+1).

What the meaning by first 2n? Is it 2+4+8+ … +2n series?
4 + 8 + 12 + .....
They want the first '2n' terms. You can guess...
1st term = 4,
2nd term = 8,
3nd term = 12,
.
.
.
.
'2n'th term = ??
It is 8n

So,
4+8+12+......+8n = 4(1+2+3....) = 4\frac{2n(2n+1)}{2}
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Algebra is the offer made by the devil to the mathematician. The devil says: `I will give you this powerful machine, it will answer any question you like. All you need to do is give me your soul: give up geometry and you will have this marvellous machine.'
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