Thread: logarithms?!
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Old January 3rd, 2008, 01:32 PM
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Quote:
Originally Posted by lemon301 View Post
So \log_{3}(3^3) would just simplify out to log 3, correct?
If you like, there is another rule you can use:
log_a(b^n) = n \cdot log_a(b)

So
log_3(3^3) = 3 \cdot log_3(3) = 3 \cdot 1 = 3

-Dan
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