Math Help Forum

Math Help Forum Feed Site Feed

Go Back   Math Help Forum > University Math Help > Advanced Probability and Statistics
Reply
 
Thread Tools Display Modes
  #1  
Old October 28th, 2009, 08:23 PM
Newbie
 
Join Date: Sep 2009
Posts: 14
Thanks: 4
Thanked 0 Times in 0 Posts
bart203 is on a distinguished road
Default Independent Geometric Random Variables

Let W1 and W2 be independent geometric random variables with parameters p1 and p2. Find
a) P(W1 = W2)
b) P(W1 < W2)
c) P(W1 > W2)
d) the distribution of min (W1 , W2)
e) the distribution of max (W1, W2)

I'm really stuck on this problem ... the geometric part is throwing me off. I would really appreciate any help! Thanks!
Reply With Quote
Advertisement
 
  #2  
Old October 28th, 2009, 09:54 PM
mr fantastic's Avatar
Flow Master

 
Join Date: Dec 2007
Location: Zeitgeist
Posts: 12,237
Country:
Thanks: 2,574
Thanked 4,761 Times in 4,193 Posts
mr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond repute
Default

Quote:
Originally Posted by bart203 View Post
Let W1 and W2 be independent geometric random variables with parameters p1 and p2. Find
a) P(W1 = W2)
b) P(W1 < W2)
c) P(W1 > W2)
d) the distribution of min (W1 , W2)
e) the distribution of max (W1, W2)

I'm really stuck on this problem ... the geometric part is throwing me off. I would really appreciate any help! Thanks!
Here's a start and something to think about:

a) \Pr(W_1 = W_2) = \sum_{i = 1}^{+ \infty} \Pr(W_1 = i \, \text{and} \, W_2 = i)


= \sum_{i = 1}^{+ \infty} (1 - p_1)^{i - 1} p_1 \cdot (1 - p_2)^{i-1} p_2 = \sum_{i = 1}^{+ \infty} [(1 - p_1)(1 - p_2)]^{i - 1} p_1 p_2


= \frac{p_1 p_2}{(1 - p_1)(1 - p_2)} \sum_{i = 1}^{+ \infty} \left[ (1 - p_1) (1 - p_2)\right]^i

and now you have the sum of an infinite geometric series.
__________________
There are two things you should never try to prove: the impossible and the obvious.

The greater danger for most of us lies not in setting our aim too high and falling short; but in setting our aim too low and achieving our mark. (Michelangelo Buonarroti)

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

Last edited by mr fantastic; October 29th, 2009 at 12:35 AM.
Reply With Quote
The Following 2 Users Say Thank You to mr fantastic For This Useful Post:
Donate to MHF
  #3  
Old October 28th, 2009, 11:18 PM
Newbie
 
Join Date: Oct 2009
Posts: 2
Country:
Thanks: 0
Thanked 1 Time in 1 Post
Juicy is on a distinguished road
Default Error

Quote:
Originally Posted by mr fantastic View Post
Here's a start and something to think about:

a) \Pr(W_1 = W_2) = \sum_{i = 1}^{+ \infty} \Pr(W_1 = i \, \text{and} \, W_2 = i)


= \sum_{i = 1}^{+ \infty} (1 - p)^{i - 1} p \cdot (1 - p)^{i-1} p = \sum_{i = 1}^{+ \infty} (1 - p)^{2i - 2} p^2


= \frac{p^2}{(1 - p)^2} \sum_{i = 1}^{+ \infty} \left[ (1 - p)^2\right]^i

and now you have the sum of an infinite geometric series.

I may be mistaking, but does it not matter that the parameters are p1 and p2 respectively and not both p?
Reply With Quote
The following users thank Juicy for this useful post:
Donate to MHF
  #4  
Old October 29th, 2009, 12:32 AM
mr fantastic's Avatar
Flow Master

 
Join Date: Dec 2007
Location: Zeitgeist
Posts: 12,237
Country:
Thanks: 2,574
Thanked 4,761 Times in 4,193 Posts
mr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond repute
Default

Quote:
Originally Posted by Juicy View Post
I may be mistaking, but does it not matter that the parameters are p1 and p2 respectively and not both p?
I will modify my post (the modification is simple, the basic argument is unchanged).

I will also note that the answer to c) is 1 - answer to a) - answer to b) .... (which saves some work).
__________________
There are two things you should never try to prove: the impossible and the obvious.

The greater danger for most of us lies not in setting our aim too high and falling short; but in setting our aim too low and achieving our mark. (Michelangelo Buonarroti)

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.
Reply With Quote
Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off
Forum Jump


All times are GMT -7. The time now is 08:42 PM.


Powered by vBulletin® Version 3.7.3
Copyright ©2000 - 2009, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0 ©2008, Crawlability, Inc.
©2005 - 2009 Math Help Forum


Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.