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Old October 29th, 2009, 04:08 PM
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Default Finding mean of poisson distribution

A store opens at 8 in the morning. from 8 until 10 customers arrive at poisson rate 6 per hour. Between 10 and 12 they arrive at a poisson rate of 10 per hour. From 12 to 2, the store closes for lunch, Finally from 2 to 5 the arrival rate drops linearly from 10 per hour at 2 to four per hour at 5. Determin the mean number of customers that enter the store on a given day.

Firstly Im not sure what to do here except maybe from 2 to 5 we can say the Mean rate is 7 per hour?

Thanks in advance!
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Old October 29th, 2009, 04:54 PM
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Just add the means per hour.

(6+6)+(10+10)+(the expected number of vistors from 2 to 5PM)

I would expect 7 on average on that 3 hours period, (10+4)/2=7

12 +20 +21=53.

I think I'm right, but who knows.

Last edited by matheagle; October 29th, 2009 at 06:07 PM.
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Old October 29th, 2009, 05:08 PM
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thanks so much. I had this but reckoned it was too easy! Thanks so much for replying I really appreciate it!
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