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Old November 1st, 2009, 09:36 AM
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Default characteristic function of linnik distrib

Let X_{i} \epsilon Linnik(\alpha), N \epsilon Fs(p), S_n=\sum_{i=1}^n X_i
with \phi_{linnik(\alpha)}= (1+|t|^{\alpha})^{-1}
Now show that p^{(1/\alpha)}S_n is again Linnik distributed.

So i need to show that p^{(1/\alpha)}S_n has characteristic funtion of the form\phi_{linnik(\alpha)}= (1+|t|^{\alpha})^{-1}

I know that \phi_{S_n}=g_N(\phi_{X(t)}) withg_N the generating function of N

So i plug in nad get g_N(t)=E(t^N)=\sum_n t^n*P(N=n)=\sum_n t^n*p(1-p)^{n-1}
=\frac{p}{(1-p)}\sum_n (t(1-p))^n=\frac{p}{(1-p)}\frac{1}{(1-(1-p)t)}
But even this is questionably since i dont know if t(1-p)<1. and even if the former is correct it does not yield the correct answer so where did i go wrong?
(i get \phi_{p^{1/\alpha}*S_n}=p (1/(1 - p) + 1/(p + Abs[t]^a)))

Last edited by isarutas; November 1st, 2009 at 09:48 AM.
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