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November 2nd, 2009, 11:51 AM
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| |  Let X be N (mu, sigma squared)
Show that the points of infection of the graph of the p.d.f. of X occur at
x = mu plus/minus sigma. |
November 2nd, 2009, 04:00 PM
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Quote:
Originally Posted by affelix  Show that the points of infection of the graph of the p.d.f. of X occur at
x = mu plus/minus sigma. | Read this thread: Points of inflection on the graph of this distribution?
__________________ There are two things you should never try to prove: the impossible and the obvious. The greater danger for most of us lies not in setting our aim too high and falling short; but in setting our aim too low and achieving our mark. (Michelangelo Buonarroti)
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