Hello,
E(X^n)=the n-th derivative of M(t) taken at t=0
And since the mean is E(X) and the variance is E(X²)-E(X)², you can do the first two questions easily.
The last two questions require that you recognize the distribution whose mgf is this one.
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shinhidora production
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Last edited by mr fantastic; November 2nd, 2009 at 04:15 PM.
Reason: Let the OP do some work - s/he can look up a table of mgf's and find the corresponding distribution themselves.
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If the moment generating of X is M (t) = exp(100t + 200t^2) 
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