Quote:
Originally Posted by CousinItt A newspaper sent a letter to 7500 persons in a town with the question "Do you agree with the decision to build a new football stadium in town?".
2100 people answered yes, 290 answered no and the rest didn't have any opinion. The newspaper took a random sample of 50 persons of the ones who didn't answer and it was showed that 22 said no, 8 said yes and 20 didn't know.
Calculate the percentage in favor of and against the decision.
The right answer is:
In favor of: 31.9%
Against: 35.5%
I just need to know how to solve it. |
You use the sample statistics for the second sample from the no opinions on the first sample to allocated all the no opinions in the first sample to the YES, NO and DON'T KNOW categories.
You have

no opinions in first sample and we allocate

to the NOs and

to the YESs. Giving total YESs of

, and NOs of

. The problem is that these do not correspond to the percentages given in the answer.
This is assuming that "didn't have any opinion" on the first sample is the same as "did not answer" which are not normally the same thing (and if they did respond with no opinion it is statistical malpractice to do what is done here).
Without a statement of how the initial sampling frame was constructed this survey is invalid, as it is not usually posible to construct a proper random sample for a mail shot without a lot of careful work.
RonL