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Old May 29th, 2009, 07:24 PM
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Default Determine the number of vectors

Determine the number of vectors \begin {bmatrix} x_1 \\ \cdots \\ x_n \end {bmatrix}, such that each x_i is either 0 or 1 and \sum _{i=1}^{n} {x_i} \geq k
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Old May 30th, 2009, 01:48 AM
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Determine the number of vectors \begin {bmatrix} x_1 \\ \cdots \\ x_n \end {bmatrix}, such that each x_i is either 0 or 1 and \sum _{i=1}^{n} {x_i} \geq k
This is equivalent to finding the probability of k or more successes in n Bernoulli trials with probability of successes 0.5, then multiplying by the total number of such vectors.

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Old May 30th, 2009, 05:36 PM
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I mean to count quantity of possbile vectors
if k=1,then \sum _{i=1}^{n} {x_i} \geq 1. There are ( \begin{array}{ccc} n \\ 1 \end{array} ) 2^{n-1} vectors

I don't confirm whether to be right
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Old May 30th, 2009, 11:43 PM
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Originally Posted by math2009 View Post
I mean to count quantity of possbile vectors
if k=1,then \sum _{i=1}^{n} {x_i} \geq 1. There are ( \begin{array}{ccc} n \\ 1 \end{array} ) 2^{n-1} vectors

I don't confirm whether to be right
There are a total of 2^n such binary vectors, and of these 1 such that \sum _{i=1}^{n} {x_i} < 1, that is the vector with all zeros. Therefore the total number of binary vectors for which \sum _{i=1}^{n} {x_i} \geq 1 is 2^n-1.

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