What's the probability of flipping n consecutive heads on a fair coin? What about an even number of consecutive heads?
For the first one, I simply got (1/2)^n, is this correct?
How will I solve the second? Any hints? There could be infinite number of arrangements as there are infinite even numbers
Yes, your first answer is correct.
For the second question, I think the question means this:
A coin is repeatedly flipped until a tail occurs. What is the probability that there was an even number of heads before the tail?
So we need to work out the probability of 0 heads followed by a tail, 2 heads followed by a tail, 4 heads followed by a tail, ... and so on. Then add these probabilities together. I'll start you off:
?
... etc
Then add these together and sum to infinity. (I make the answer .)
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