Probability using binomial distribution

jake.davis · #1 $Old$ November 2nd, 2009, 01:19 PM

I was hoping someone might check my work as the answer seems a little off:

A die is thrown 20 times and a success id defined as a one or a six on the upface of the die.

Use the binomial distribution to determine the probability of getting exactly five successes in the 20 trials.

I came up with:

C(20,5)*((2/6)^5)*((4/6)^15)

=0.1462

Any help would be appreciated.

Plato · #2 $Old$ November 2nd, 2009, 01:31 PM

Quote:

Originally Posted by jake.davis $View Post$

A die is thrown 20 times and a success id defined as a one or a six on the upface of the die.
Use the binomial distribution to determine the probability of getting exactly five successes in the 20 trials.
C(20,5)*((2/6)^5)*((4/6)^15)

Correct