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November 16th, 2009, 08:47 PM
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| |  Probability help
Hi, can anyone help me with this question, i am stuck: 1. Higbee Manufacturing Corp. has recently received 5 cases of a certain part from one of its suppliers. The defective rate for the parts is normally 5%, but the supplier has just notified Higbee that one of the cases shipped to them has been made on a misaligned machine that has a defect rate of 97%. So the plant manager selects a case at random and tests a part. - What is the probability that the part is defective?
- Suppose the part is defective, what is probability that this is from the case made on the misaligned machine?
- After finding that the first was defective, suppose a second part from the case is tested. However, this part is found to be good. Using the revised probabilities from part (b) compute the new probability of these parts being from the defective case.
- Do you think you would obtain the same posterior probabilities as in part (c) if the first part was not found to be defective, but the second part was?
- Suppose, because of the other evidence, the plant manager was 80% certain this case was the one made on the misaligned machine. How would your answer to part (b) change?
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November 17th, 2009, 03:53 AM
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Quote:
Originally Posted by Anam123  Hi, can anyone help me with this question, i am stuck: 1. Higbee Manufacturing Corp. has recently received 5 cases of a certain part from one of its suppliers. The defective rate for the parts is normally 5%, but the supplier has just notified Higbee that one of the cases shipped to them has been made on a misaligned machine that has a defect rate of 97%. So the plant manager selects a case at random and tests a part. - What is the probability that the part is defective?
- Suppose the part is defective, what is probability that this is from the case made on the misaligned machine?
- After finding that the first was defective, suppose a second part from the case is tested. However, this part is found to be good. Using the revised probabilities from part (b) compute the new probability of these parts being from the defective case.
- Do you think you would obtain the same posterior probabilities as in part (c) if the first part was not found to be defective, but the second part was?
- Suppose, because of the other evidence, the plant manager was 80% certain this case was the one made on the misaligned machine. How would your answer to part (b) change?
| I suggest drawing a tree diagram. Then it should be clear that:
(a) (1/5) (0.97) + (4/5) (0.05) = ....
(b) (1/5) (0.97)/[(1/5) (0.97) + (4/5) (0.05)] = ....
etc.
__________________ There are two things you should never try to prove: the impossible and the obvious. The greater danger for most of us lies not in setting our aim too high and falling short; but in setting our aim too low and achieving our mark. (Michelangelo Buonarroti)
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