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May 3rd, 2008, 07:18 AM
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| |  Ti-89 Titanium Solving equation systems
I've got the following two source equitations:
1.
(c*ucde + ((l*ilde) + uc)/r + (l*ilde + uc - us)/r) = 0
2.
(-c*ucde + il + (alfa*(l*ilde + uc)/r)) = 0
I'm looking for a symbolic solution in the following format:
ucde -> -((-2 il r - alfa us)/((2 + alfa) c r))
ilde -> -((il r + 2 uc + alfa uc - us)/((2 + alfa) l))
How sholud i enter this question on my Ti-89 Titanium.
The jpg file contains the solution in the mathematica program, but i need the solution on my TI.89 titanium. |
May 3rd, 2008, 07:21 AM
|  | A Cute Angle | | Join Date: Mar 2008 Location: P(I'm here)=1/3, P(I'm there)=t+1/3
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Hello,
I think you should do this way (but I'm not sure because I don't know what these letters represent) :
solve(first equation and second equation, [x,y])
where x and y are the variables.
I put it initially, but it seems that it doesn't look useful without it... I don't know what ilde and ucde represent. But if you're dealing with variables containing more than one letter in their name, I advice you to change their names into single letters.
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Last edited by Moo; May 3rd, 2008 at 07:36 AM.
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May 3rd, 2008, 10:56 AM
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This is what I typed into my TI89:
solve((c*ucde + ((l*ilde) + uc)/r + (l*ilde + uc - us)/r) = 0 and (-c*ucde + il + (alfa*(l*ilde + uc)/r) = 0, [ucde,ilde])
This is what I got:
Error: Argument must be a variable name
What am I doing wrong? |
May 3rd, 2008, 10:57 AM
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Is ucde a name or u*c*d*e ?
Because your calculator will understand it as u*c*d*e
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May 3rd, 2008, 11:04 AM
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Sorry
solve((c*ucde + ((l*ilde) + uc)/r + (l*ilde + uc - us)/r) = 0 and (-c*ucde + il + (alfa*(l*ilde + uc)/r) )= 0, [ucde,ilde]) |
May 3rd, 2008, 11:05 AM
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ucde, ilde, uc are variable names. |
May 3rd, 2008, 11:26 AM
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