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Old October 13th, 2009, 04:53 PM
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Default Optimization; cylinder inside sphere

Find the dimensions(r and h) of the right circular cylinder of greatest Surface Area that can be inscribed in a sphere of radius R.

my work so far

SA=2\pi r^2+2\pi rh

r^2 + (\frac{h}{2})^2 = R^2

h=2\sqrt{R^2-r^2}

SA=2\pi r^2+4\pi r\sqrt{R^2-r^2}

\frac{dSA}{dr}=4\pi r+4\pi (\sqrt{R^2-r^2}+\frac{-2r^2}{2\sqrt{R^2-r^2}})

I tried setting that equal to zero, but I wasn't coming up with the right answer

The answer in the book(not mine): r=\sqrt{\frac{5+\sqrt{5}}{10}}R
h=2\sqrt{\frac{5-\sqrt{5}}{10}}R

Can anyone see my error, or did I make one?

Last edited by Tclack; October 13th, 2009 at 04:54 PM. Reason: clarification
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cylinder, max, min, optimization, sphere

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