Another simpleish incuction proof

sirellwood · #1 $Old$ November 5th, 2009, 11:13 AM

Prove by induction that:

$\sum_{k=1}^n k(k+1)....(k+a)$ = $\frac{1}{a+2}$ n(n+1)(n+2)....(n+a+1)

for all n and a Natural Numbers

CaptainBlack · #2 $Old$ November 6th, 2009, 01:10 PM

Quote:

Originally Posted by sirellwood $View Post$

Prove by induction that:

$\sum_{k=1}^n k(k+1)....(k+a)$ = $\frac{1}{a+2}$ n(n+1)(n+2)....(n+a+1)

for all n and a Natural Numbers

What have you attempted, and where are you having difficulties.

CB