I'm little confused with this excersise.....

if the derivative of y=k(x) equals 2 when x =1 , what is the derivative of

a k(2x) when x = 1/2?

b k(x+1) when x=0

c k((1/4)x) when x=4

in this excersise , the chain rule should be applied, but I don't know how. Can I get some help?

You are told that .


Now use the chain rule on the other functions...



Now let .


Use a similar approach for the rest...

__________________
Two things are infinite - The Universe and Human Stupidity. Though I'm not too sure about the universe...

Let u= 2x. Then [math]\frac{dk(2x)}{dx}= \frac{dk(u)}{du}\frac{du}{dx} and, of course, when x= 1/2, u= 1.

Let u= x+1. When x= 0, u= 1.

Let u= (1/4)x. When x= 4, u= 1.