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#1

$Old$ November 12th, 2009, 06:48 AM

puravida12 $puravida12 is offline$

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$Default$ Finding Derivatives

f(x) = e^(2pix)

f(x)= x^(e2pi)

f(x)= (epi)^2x

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#2

$Old$ November 12th, 2009, 07:00 AM

pencil09 $pencil09 is offline$

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Quote:

Originally Posted by puravida12 $View Post$

f(x) = e^(2pix)

f(x)= x^(e2pi)

f(x)= (epi)^2x

i'll try the first one....
$f(x) = e^{(2pix)}$
you can find the f'(x) with chain rule method, and remember this one

Quote:

$f(x) = e^{x}$
$f'(x) = e^{x}$

so, $f'(x) =(2) (pi) e^{(2pix)}$

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#3

$Old$ November 12th, 2009, 07:03 AM

jeneverboy $jeneverboy is offline$

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Or,

$f(x) = e^{ax}$
$f'(x) = a e^{ax}$

and the power rule:

$f(x) = x^{a}$
$f'(x) = a x^{a-1}$

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calculus ab, chain rule, derivatives

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