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November 17th, 2009, 06:44 PM
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| |  Derivative
can you show me step by step how the
dy/dx of the arcsine (square root of 2t) = (the square rood of 2)/ ( the square root of 1-2t^2) |
November 17th, 2009, 07:04 PM
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Quote:
Originally Posted by 10parentc  can you show me step by step how the
dy/dx of the arcsine (square root of 2t) = (the square rood of 2)/ ( the square root of 1-2t^2) |
if  is a function of  ... ![\frac{d}{dt}\left[\arcsin(u)\right] = \frac{u'}{\sqrt{1-u^2}}](http://www.mathhelpforum.com/math-help/latex2/img/1a5db9916580ab4565f73be8a79b5bd2-1.gif "\frac{d}{dt}\left[\arcsin(u)\right] = \frac{u'}{\sqrt{1-u^2}}")
for your problem, it appears that  |
November 17th, 2009, 07:12 PM
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Quote:
Originally Posted by 10parentc can you show me step by step how the
dy/dx of the arcsine (square root of 2t) = (the square rood of 2)/ ( the square root of 1-2t^2) | Asked here: derivitive
Thread closed.
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