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Old November 18th, 2009, 06:22 AM
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Default Maclaurin series

When we expand maclaurin series for function y = ln(1+x) then we need the condition -1 < x \le 1. Why???
Pl help me. Thanks so much.
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Old November 18th, 2009, 04:01 PM
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When we expand maclaurin series for function y = ln(1+x) then we need the condition -1 < x \le 1. Why???
Pl help me. Thanks so much.
First get the series. Then use the ratio test to find the interval of convergence of the series.
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Old November 18th, 2009, 04:13 PM
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Actually, root test is faster, but it'd yield the same interval of convergence.
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Old November 21st, 2009, 06:13 PM
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Yes, i understand. But why in the proof of Taylor series (or Maclaurin series) we don't need any conditions for x and f(x)?
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Old November 21st, 2009, 09:05 PM
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Yes, i understand. But why in the proof of Taylor series (or Maclaurin series) we don't need any conditions for x and f(x)?
I think you'll find most statements of the Taylor Series do include something about convergence. See for example Taylor series - Wikipedia, the free encyclopedia
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