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#1

$Old$ September 18th, 2007, 04:22 PM

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Could someone help me with this integral?

$\int\,x\sqrt{1+x}\,dx$

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#2

$Old$ September 18th, 2007, 04:26 PM

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According to the change of variables defined by $u=x+1$ , the integral becomes to

$\int x\sqrt{x+1}\,dx=\int(u-1)\sqrt u\,du$

Now you can take it from there.

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#3

$Old$ September 18th, 2007, 04:51 PM

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Ah, okay. Thanks for helping.

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#4

$Old$ September 18th, 2007, 04:53 PM

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You're welcome.

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Here on MHF we all have the predisposition to help, and when you post a question, it is answered quickly.

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