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#1

$Old$ September 18th, 2007, 05:00 PM

taurus $taurus is offline$

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I am a bit stuck on this:
(note: | = intergration symbol)

2|6-3|6

Now i think im right at that point. Not sure what to do from there?

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#2

$Old$ September 18th, 2007, 05:03 PM

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I don't get very well what you want.

Use some of LaTeX.

See the LaTeX Help forum.

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$Old$ September 18th, 2007, 05:05 PM

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$\left[ 2\int_3^5 6\right] - \left[ 3\int_3^5 6\right]$

does that make more sense?

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$Old$ September 18th, 2007, 05:10 PM

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Yeah a lot.

It's very easy, since

$\int dx=x+k$ , then $\int_a^b dx=b-a$

Does that make sense?

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#5

$Old$ September 18th, 2007, 05:13 PM

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wait so i say 5-3? what about the 6 and 3 and 2?

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$Old$ September 18th, 2007, 05:22 PM

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Quote:

Originally Posted by taurus $View Post$

wait so i say 5-3? what about the 6 and 3 and 2?

$2\int_3^5 6 - 3\int_3^5 6$

You're integrating with respect to what?

We'll assume dx.

Thus, $2\cdot [6(5) - 6(3)] - 3\cdot [6(5)-6(3)] = (2\cdot 12) - (3\cdot 12) = 24 - 36 = -12$

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$Old$ September 18th, 2007, 05:51 PM

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wait i think i got the question wrong, suppose we have:
$\int_3^5 f(x) dx = 6$ , $\int_3^6 f(x) dx = 5$ , $\int_3^5 g(x) dx = 6$

now it asks to find the value of the following integrals:
$\int_3^5 2f(x) -3 g(x) dx =$
??
?? any ideas

Last edited by taurus; September 20th, 2007 at 04:47 AM.

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