need a bit of help with derivatives...thanks - Math Help Forum

$Math Help Forum$

$Go Back$		Math Help Forum > University Math Help > Calculus
$Reload this Page$ need a bit of help with derivatives...thanks

Download MHF Flyer

Mark Forums Read

$Reply$

#1

$Old$ October 1st, 2007, 09:54 PM

mathaction $mathaction is offline$

Banned

Join Date: Oct 2007

Posts: 45

Country:

United States

Thanks: 12

Thanked 0 Times in 0 Posts

$mathaction is on a distinguished road$

$Default$ need a bit of help with derivatives...thanks

need some help with this one...

$Reply With Quote$

Advertisement

#2

$Old$ October 1st, 2007, 10:06 PM

$Jhevon's Avatar$

Jhevon $Jhevon is offline$

vs Jhevon

Join Date: Feb 2007

Location: New York, USA

Posts: 11,104

Country:

Jamaica

Thanks: 2,610

Thanked 4,271 Times in 3,970 Posts

$Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$

$Default$

Quote:

Originally Posted by mathaction $View Post$

need some help with this one...

use the product rule: $\frac d{dx} f(x)g(x) = f'(x)g(x) + g'(x)f(x)$

here: $f(x) = t^2 + 4$ and $g(x) = e^t$

$Reply With Quote$

#3

$Old$ October 1st, 2007, 10:31 PM

mathaction $mathaction is offline$

Banned

Join Date: Oct 2007

Posts: 45

Country:

United States

Thanks: 12

Thanked 0 Times in 0 Posts

$mathaction is on a distinguished road$

$Default$

Quote:

Originally Posted by Jhevon $View Post$

use the product rule: $\frac d{dx} f(x)g(x) = f'(x)g(x) + g'(x)f(x)$

here: $f(x) = t^2 + 4$ and $g(x) = e^t$

ok...i came up with this...

e^t*3t^2+e^t*t^3+4

$Reply With Quote$

#4

$Old$ October 1st, 2007, 10:33 PM

$Jhevon's Avatar$

Jhevon $Jhevon is offline$

vs Jhevon

Join Date: Feb 2007

Location: New York, USA

Posts: 11,104

Country:

Jamaica

Thanks: 2,610

Thanked 4,271 Times in 3,970 Posts

$Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$

$Default$

Quote:

Originally Posted by mathaction $View Post$

ok...i came up with this...

e^t*3t^2+e^t*t^3+4

that's incorrect. try one more time. and use parentheses

$Reply With Quote$

#5

$Old$ October 1st, 2007, 11:04 PM

$Jhevon's Avatar$

Jhevon $Jhevon is offline$

vs Jhevon

Join Date: Feb 2007

Location: New York, USA

Posts: 11,104

Country:

Jamaica

Thanks: 2,610

Thanked 4,271 Times in 3,970 Posts

$Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$

$Default$

Quote:

Originally Posted by mathaction $View Post$

need some help with this one...

$z'(t) = 3t^2e^t + \left( t^3 + 4 \right)e^t = \left( t^3 + 3t^2 + 4 \right)e^t$

$Reply With Quote$

#6

$Old$ October 1st, 2007, 11:06 PM

mathaction $mathaction is offline$

Banned

Join Date: Oct 2007

Posts: 45

Country:

United States

Thanks: 12

Thanked 0 Times in 0 Posts

$mathaction is on a distinguished road$

$Default$

oh ok...so its like just combining like terms...

$Reply With Quote$

#7

$Old$ October 2nd, 2007, 07:21 AM

$Jhevon's Avatar$

Jhevon $Jhevon is offline$

vs Jhevon

Join Date: Feb 2007

Location: New York, USA

Posts: 11,104

Country:

Jamaica

Thanks: 2,610

Thanked 4,271 Times in 3,970 Posts

$Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$ $Jhevon has a reputation beyond repute$

$Default$

Quote:

Originally Posted by mathaction $View Post$

oh ok...so its like just combining like terms...

yes, at the end, after i took derivatives

$Reply With Quote$

$Reply$

« ln to the ln | Top | Evaluating Limits Analyticall »

Thread Tools
$Show Printable Version$ Show Printable Version $Email this Page$ Email this Page
Display Modes
$Linear Mode$ Linear Mode $Hybrid Mode$ Switch to Hybrid Mode $Threaded Mode$ Switch to Threaded Mode

Posting Rules
You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is Off Trackbacks are Off Pingbacks are Off Refbacks are Off

Forum Jump

All times are GMT -7. The time now is 09:06 AM.

your link here Sponsors

rv solar, e-learning,

Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.